|
Author |
Message |
howadtse
Joined: 22 Sep 2004Posts: 6
|
Posted: Mon Mar 21, 2005 9:44 pm Post subject: Special Inequality
|
|
|
a,b,c為正實數 求證:
(a+3c)/(a+2b+c)+4b/(a+b+2c)-8c/(a+b+3c)>=-17+12*2^0.5
|
|
|
|
|
howadtse
Joined: 22 Sep 2004Posts: 6
|
Posted: Mon Mar 21, 2005 9:46 pm Post subject:
|
|
|
有冇d咩方法丫??
|
|
|
|
|
Soarer
Frequent VisitorJoined: 18 Jan 2004Posts: 213
Location: Hong Kong
|
Posted: Mon Mar 21, 2005 10:29 pm Post subject:
|
|
|
let x=a+2b+c, y=a+b+2c,z=a+b+3c and it should not be too difficult.
|
|
|
|
|
|
|
|
All times are GMT + 8 Hours
|
|
|
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
|
|